In this lesson we will examine three of the main theories used to define acids and bases, review the pH scale, its applications, and its development, as well as identify acids and bases as strong or weak, based on their dissociation.
The terms acid and base are often used to classify substances used in chemical reactions. The specific definition of each term depends on which acid-base theory we choose to use. The three main acid-base definitions we should be familiar with are those credited to Arrhenius, Brønsted-Lowry, and Lewis.
The Arrhenius Concept defines acids as substances that produce H+ (hydrogen ions) in solution.
HCl(aq) → H1+(aq) + Cl1–(aq)
H3PO4(aq) → 3H1+(aq) + PO43–(aq)
According to this concept, hydrochloric and phosphoric acids are acids because they dissociate to make hydrogen ions in solution.
It defines bases as substances that produce OH– (hydroxide ions) in solution.
NaOH(aq) → Na1+(aq) + OH1–(aq)
Ca(OH)2(aq) → Ca2+(aq) + 2OH1–(aq)
According to this concept, sodium and calcium hydroxides are bases because they dissociate to make hydroxide ions in solution.
The Brønsted-Lowry Model defines acids as proton donors. In other words, acids donate H+ (hydrogen ions) in solution.
HCl(aq) + H2O(l) → H3O1+(aq) + Cl1–(aq)
H3PO4(aq) + H2O(l) → H3O1+(aq) + H2PO41–(aq)
According to this model, hydrochloric and phosphoric acids are acids because they donate a hydrogen ion to the water forming the hydronium ion.
It defines bases as proton acceptors. In other words, bases accept H+ (hydrogen ions) in solution.
NH3(aq) + H2O(l) → NH41+(aq) + OH1–(aq)
According to this model, NH3(aq) is a base because it accepts a hydrogen ion to form an ammonium ion.
The first equation sets up two interesting relationships. Not only does the ammonia accept a hydrogen ion to become the ammonium ion, the hydroxide ion could accept a hydrogen ion from the ammonium and become water. These two relationships make the ammonia/ammonium ion and the water/hydroxide ion conjugate acid/base pairs.
In Lewis’ Theory, acids are electron pair acceptors in solution, while bases are electron pair donors in solution.
BF3(aq) + :NH3(aq) → F3B:NH3
According to this theory, BF3(aq) is an acid because it accepts the electron pair from NH3(aq) which is the base because it donates the electron pair to BF3(aq).
pH represents the relative acidity of a solution based on hydrogen ion or hydronium ion concentration and can be found using either of the following equations:
The amphoteric nature of pure water contributes to its neutral nature. This means that water can act as an acid or a base due to the concept known as autoionization, which is shown in the following two examples.
H2O(l) → H1+(aq) + OH1–(aq)
According to the Arrhenius Concept, water (in the equation above) is acting as an acid by producing hydrogen ions as well as a base by producing hydroxide ions.
2H2O(l) → H3O1+(aq) + OH1–(aq)
According to the Brønsted-Lowry Model one water molecule (in the equation above) is acting as an acid by donating a hydrogen ion to the other molecule of water forming a hydronium ion. The water molecule that is accepting the hydrogen ion is acting as the base.
If we write the equilibrium expression for this we get:
Kw = [H3O1+ ][OH1– ] = 1.0×10–14 at 25 °C
We can solve for the [H3O1+ ] or [OH1– ] based on the previous equation.
For every H3O1+ produced, one OH1– is made so:
[H3O1+ ][OH1– ] = 1.0×10–14 becomes
[x][x] = 1.0×10–14
x2 = 1.0×10–14
x = 1.0×10–7
Therefore, [H3O1+ ] = 1.0×10–7 = [OH1–]
If you are given either the [H3O1+ ] or [OH1– ], you can solve for the other.
Given [OH1– ] = 1.0×10-5 M at 25°C, solve for [H3O1+ ].
Kw = [H3O1+ ][OH1– ] = 1.0×10–14 M2
[H3O1+ ][1.0×10-5 M] = 1.0×10–14 M2
Substances other than water can also be amphoteric. Let’s look at a hydrated aluminum hydroxide ion as an example.
[Al(H2O)4(OH)2]1++ NaOH ↔ Al(H2O)3(OH)3 + OH1–
Then a water of hydration from [Al(H2O)4(OH)2]1+ donates the hydrogen ion to become the third hydroxide ion it is acting as a Brønsted-Lowry acid.
[Al(H2O)4(OH)2]1+ + HCl ↔ [Al(H2O)5OH]2+ + Cl1–
When a hydroxide from [Al(H2O)4(OH)2]1+ accepts the hydrogen ion to create the fifth water of hydration it is acting as a Brønsted-Lowry base.
Acids and bases can be concentrated or dilute, weak or strong. Do not confuse the first two which describe the solution concentration, with the last two which describe the amount of dissociation.
Given that [H3O1+] = 1.0×10-2 M at 25°C, what is the [OH1– ]?
The correct answer is D. Using the equation: Kw = [H3O1+][OH1– ] = 1.0×10-14 M2 and substituting the given concentration for [H3O1+ ]:
[1.0×10-2 M][OH1– ] = 1.0 ×10-14 M2
In the reaction CaO(s) + H2O(l) Ca(OH)2(aq) calcium oxide acts as ________
The correct answer is C. Calcium oxide accepts both hydrogen and a hydroxide from the water to become calcium hydroxide.