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Work, Energy, Power, and Momentum

Objective

The lesson will cover the basics of energy, work, power, and momentum.

Energy

Energy is everywhere around us. It is a fundamental quantity that all physical systems contain in one form or another. The concept of energy is not difficult to understand. Energy is a quantity that can be moved or transferred from one place or from one form to another, and like mass, it cannot be created or destroyed. The simplest way to define energy is that energy is the ability to do work. All energy and work can be interconverted between actual work done, potential energy, and kinetic energy. Energy is also defined as the amount of work required to change the state of a physical system (e.g., from liquid to gas) Potential energy is sometimes called “stored energy.”

Here are some of the ways that energy is stored:

  • Chemical energy – Energy that is stored in chemical bonds. For example, remember the breakfast that you ate this morning? The calories contained in the chemical bonds are now available to your muscles as chemical potential energy.
  • Gravitational energy – Energy that is stored in the gravitational field between two masses. This is sometimes also called potential energy.
  • Elastic energy – Energy that is stored in objects that stretch or bend, like your skin, trees, rubber bands, strings, and diving boards.
  • Kinetic energy is sometimes viewed as energy of motion, or expressed energy.
  • A moving object has kinetic energy due to its motion.
  • A falling object possesses both potential and kinetic energy.
  • A hot stove possesses both potential and kinetic energy.

How do we change energy between its various forms? Sometime this occurs naturally, as when an object falls toward the earth. “working.” Work is done when energy is transferred from one place to another. More specifically, the amount of work done equals the amount of transferred energy. Here are a few examples of when work is done:

  • Chemical energy stored in a battery transfers to radiant energy from a light bulb.
  • Gravitational potential energy of elevated water transfers into kinetic energy as the water cascades over a water wheel.
  • Chemical energy stored in the muscles of a mountain climber transfers into lifting energy as she climbs up a mountain.
  • Random kinetic energy of individual water molecules in steam transfers into kinetic energy in a turbine.

In a parallel fashion, energy can be transferred from one form of storage into another. Using the examples from above, the electromotive force in a battery enables the energy to transfer from chemical energy to radiant and heat energies in the circuit. Similarly, the gravitational force enables energy to transfer from potential energy into kinetic and heat energies through the turning of a water wheel.

Question

How would you explain the operation of a car in terms of energy and work? Think about all the ways that energy is converted, used, and stored during the car’s operation. Also consider how forces enable the energy to transfer from one mode into another. Click on the following link to check your explanation:

Reveal Answer

Chemical energy is stored as chemical bonds in the gasoline. When gasoline combusts, the liquid is changed to a gas through combustion, and the gas expands to do work on the pistons. The pistons transfer the energy into kinetic energy that turns the drive shaft and the tires. The frictional force between the tires and the road transfers that kinetic energy to the kinetic energy of the car. Hence, the car moves.

How do we calculate work? When objects are moved, work is done when the applied force is in the same direction that the object will be moved. Motion in any other direction than the proposed direction of motion does not count toward the work being done. For example, when an object is lifted vertically, work (W) is calculated by taking the product of the force applied (F) and height that it is lifted (h). In this case the height the object is lifted against gravity becomes the distance, and the work is called “gravitational work.” Thus the normal work equation Work = force(f) x distance(d) becomes:

W = F h

The force that we’re lifting against is, of course, the gravitational force. This force is calculated by taking the product of an object’s mass (m) times the strength of the gravitational field (g = 9.8 N/kg on the surface of the earth). So, our equation becomes:

Work = m g h

For example, how much work would it take to lift a 40 kg barbell to a height of 2 meters from the ground?

W = m g h = 40 kg · (9.8 N/kg) · 2 m = 784 J

Note: m x g is the weight of an object

Question

Practice Question: How much work would it take to carry the same barbell 5 meters across the room?

  1. 784 J
  2. 3784 J
  3. 0 J
  4. 5 J

Reveal Answer

The correct answer is C. No work is done because the applied force (gravity in this case) is not in the direction of the motion. The calculation looks like this: W = mgh = 40 kg · (9.8 N/kg) · 0 m = 0 J

Working Simply

Sometimes we don’t have the physical strength or mechanical power to apply enough force to get a job done. Simple machines are devices that make work easy. They can help us by changing the direction of the applied force, reducing the magnitude of the input force, or helping to add speed to the rate at which work is done. This sounds almost magical, like we’re getting something from nothing. But, alas, the law of energy conservation still governs the universe. Reduced forces applied through simple machines are a consequence of increasing distances. For example, the equation

Work in = Work out

(F d) in = (F d ) out

Where F = force, and d = distance, the formula shows how an ideal machine transfers no energy to heat by frictional forces, since “work in” equals “work out.”

A classic example, the lever, can significantly reduce the input forces and yield large output forces. The handle is easily moved over a large distance and an object is pried through a small distance as shown in the following figure:

A simple fulcrum
The work equation can be written as follows in this case:

(F d) in = (F d ) out

The mechanical advantage (MA) of a simple machine is the ratio between the output force (F out) to the input force (F in):

Mechanical Advantage formula
For example, we can calculate the mechanical advantage for a worker using a hammer to pry out a nail. A 20 N force is applied to the handle that results in an 80 N force that pulls up on the nail. The mechanical advantage (MA) is calculated as follows:

MA
The inclined plane is another example of a simple machine. Instead of lifting directly up against the gravitational force, the inclined plane enables the user to push with a smaller force a greater distance diagonally up the ramp. For example, a 130N box is pushed up the incline shown in the picture below.

Incline
We can calculate the force needed to push it up the ramp as follows:

(F d) in = (F d ) out

F ·13m = 130N · 5m

F = 50 N

Calculate the mechanical advantage for this inclined plane. Reveal Answer

Pulleys, wedges, ramps, and screws are some other examples of simple machines that offer a mechanical advantage. It is a good exercise to think about how these simple machines save us work in our everyday lives.

Working Powerfully

What is the relationship between energy, work, and power? Power (P) is the rate at which work is done. For example, 100-Watt light bulb uses twice as much energy in a second as a 50-Watt light bulb. The following equation can be used to calculate power:

Power formula
Where E transferred is the energy that is transferred in the process of doing work and P is the total power of the system.

To calculate the power output of a 150N child that climbs 5 meters up a rope in 10 seconds, the following calculation is made:

Example power

Question

Who is more powerful: a man who lifts a 200-N barbell 2 meters vertically in 2 seconds, or a boy who lifts a 100-N barbell 1 meter in 0.5 seconds?

Reveal Answer

They both have the SAME power:
Question power
Question power 2

Conserving Momentum

Like energy and mass, the momentum of a system is also conserved. Momentum (p) is a product of an object’s mass (m) and its velocity (v):

p = m v

In other words, momentum is a product of a mass in motion. Momentum also has direction associated with it and is considered a vector. For example, we can calculate the momentum of a 2000 kg car heading north at a speed of 20 m/s.

p = m v = 2000kg · 20 m/s = 40,000 kg m/s north

But what about momentum being conserved? This concept is a consequence of Newton’s second law and can be written as:

Net force
The equation now becomes:

Fnet = mΔv / Δt = Δp

or Fnet(Δt)= m(Δv) = Δp

Fnet is the net force of the system, Δv is the change in velocity, Δt is the change in time, and Δp is the change in momentum. The term Fnet (Δt) is called impulse, and is exactly the same quantity as m(Δv) . It gives us another way to view momentum.

If there is no net force applied to a system, then this implies that Δp is zero. In other words, with no unbalanced force on a system there is no momentum change.

where pi is the initial momentum of the system and pf is the final momentum of the system.

For example, consider a billiard ball moving at 2 m/s that squarely strikes an identical billiard ball that’s at rest. The moving ball stops and the momentum is completely transferred to the other ball, which picks up a speed of 2 m/s. Momentum is NOT conserved for the first billiard ball alone because it experiences a net force. Momentum IS conserved for the SYSTEM of both balls because the collision forces are internal to the system.

What if two objects of different masses collide? For example, what if a 2000-kg boxcar moving at 30 m/s hits and links with a 1000-kg boxcar that’s initially at rest? How fast does the combination move after the collision? To answer this, we must note that the amount of moving mass increases after the collision. This means that the speed of the system must decrease so that the momentum is conserved.

Another example of momentum conservation is in the operation of rockets. As a rocket ejects combusted gases rearward at high velocities, the more massive rocket is propelled forwards at a lesser velocity. In other words, the backward momentum of the exhaust gases equals the forward momentum of the rocket.

Try this one on your own. A 20-kg child holding a 2-kg brick is standing still on the slick surface of an ice skating rink. She throws the brick forward at a speed of 5 m/s. Completely describe her resulting motion and calculate her speed. Reveal Answer

answer

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