{"id":115,"date":"2017-09-04T04:31:47","date_gmt":"2017-09-04T04:31:47","guid":{"rendered":"http:\/\/americanboard.org\/Subjects\/general-science\/?page_id=115"},"modified":"2017-09-21T13:47:32","modified_gmt":"2017-09-21T13:47:32","slug":"electricity","status":"publish","type":"page","link":"https:\/\/americanboard.org\/Subjects\/general-science\/electricity\/","title":{"rendered":"Electricity"},"content":{"rendered":"<div class=\"twelve columns\" style=\"margin-top: 10%;\">\n<div class=\"advance\"><a class=\"button button-primary\" href=\"http:\/\/americanboard.org\/Subjects\/general-science\/mechanical-waves\">\u2b05 Previous Lesson<\/a>\u00a0<a class=\"button\" href=\"http:\/\/americanboard.org\/Subjects\/general-science\/physics\">Workshop Index<\/a>\u00a0<a class=\"button button-primary\" href=\"http:\/\/americanboard.org\/Subjects\/general-science\/magnetism-and-electromagnetism\">Next Lesson \u27a1<\/a><\/div>\n<p><!-- CONTENT BEGINS HERE --><\/p>\n<h1 id=\"title\">Electricity<\/h1>\n<section>\n<h3>Electrostatics<\/h3>\n<p>What is the reason for the warnings printed on gas pumps cautioning us not to get in and out of the car when we\u2019re pumping gas? The reason is that cars pick up electrostatic charges as they run, and the car\u2019s tires insulate that charge from the ground. <abbr title=\"the study of electrical charges at rest on objects.\">Electrostatics<\/abbr> is the study of electrical charges on objects at rest.<\/p>\n<p>There are two fundamental charges: positive and negative. We know that similarly charged objects repel and oppositely charged objects attract. Besides this, objects that are neutral (i.e. objects with an equal amount of positive and negative charge) are attracted to both positive and negative objects. Why do we know this? Let\u2019s first review the basic model of the atom.<\/p>\n<p>The very center of the atom is a tiny concentrated region that contains positive particles (protons) and neutral particles (neutrons), called the nucleus. The number of protons in the nucleus uniquely determines what element it is. This number will not change unless a \u201cdrastic\u201d nuclear event occurs (i.e. fission or fusion). In the large region of space around the tiny nucleus there is likelihood that you will find negative particles (electrons). In neutral atoms, the number of electrons equals the number of protons. In order for an object to gain a negative electric charge, it gains extra electrons. To pick up a positive charge, the object loses electrons. Thus, electrons are the \u201cmobile fluid\u201d responsible for charging objects. An object will <em>always<\/em> have the same amount of protons before and after gaining an electrostatic charge.<\/p>\n<p>Some elements are naturally good conductors of electricity. <abbr title=\"a material in which electrons flow easily from atom to atom.\">Conductors<\/abbr> are materials in which electrons flow easily from atom to atom. Metals are excellent examples of conductors. <abbr title=\"an insulating material in which the electrons are tightly bound to a particular nucleus and is highly resistant to electric current.\">Dielectrics<\/abbr>, or insulators, are materials in which the electrons are tightly bound to a particular nucleus. Rubber, plastic, and air are examples of good insulators. Under conditions with very high voltages, even insulators may have electrons travel throughout the material.<\/p>\n<p>Why are neutral conductors and neutral insulators attracted to charged objects? The explanation is a little different for each. When a negatively charged object is brought near a conductor, the electrons in the conductor are repelled by the electrons in the charged object. The free electrons in the rod are forced to move to the opposite side of the rod, leaving the positive nuclei to attract the negative object. This process is called electric induction and is represented in the following diagram:<\/p>\n<p><center><img decoding=\"async\" src=\"http:\/\/americanboard.org\/Subjects\/Images\/gensci\/img\/Mod5Fig20s.jpg\" alt=\"Electric Induction\" \/><\/center>In contrast, when a charged object is brought near a dielectric (insulator), the electrons will not move to the one side of the entire object. Rather, the electrons tend move within the atom such that the atoms are polarized. For example, if a negative balloon is brought near a wall, electrons in the atom of the wall are repelled to the opposite side of the nucleus. This leaves the positive nucleus in close proximity to the negative object and they attract one another. This process of polarization is represented in the following diagram:<\/p>\n<p><center><img decoding=\"async\" src=\"http:\/\/americanboard.org\/Subjects\/Images\/gensci\/img\/Mod5Fig21s.jpg\" alt=\"Electric Polarization\" \/><\/center><\/p>\n<section class=\"question\">\n<h4>Question<\/h4>\n<p>In an electrostatics experiment, two pieces of tape attract each other. The <b>most\u00a0<\/b>you can\u00a0conclude is that:<\/p>\n<ol>\n<li>at least one of the pieces of tape must be charged.<\/li>\n<li>both pieces of tape must be negatively charged<\/li>\n<li>both pieces of tape must be oppositely charged.<\/li>\n<li>you did the experiment incorrectly.<\/li>\n<\/ol>\n<p><a class=\"button button-primary q-answer\"> Reveal Answer <\/a><\/p>\n<p class=\"q-reveal\">The correct answer is A. It is tempting to answer C because we know that oppositely charged objects attract, but that is not the only case in which we observe an attraction. Neutral objects also attract charged objects, so all we can confidently conclude in this question is that at least one of the pieces of tape is charged. The other piece of tape could be neutral or oppositely charged.<\/p>\n<\/section>\n<h3>Electric Fields<\/h3>\n<p>In the vicinity of charged objects, there exists an electric field in which other charged objects will experience forces. The charged objects have \u201clines of force\u201d or \u201cflux lines\u201d emanating from them. The direction of the force exerted on a positive test charge placed near a charged object is shown by placing arrowheads pointing into the object to represent a negatively charged body, or arrowheads pointing out of the object if it is a positively charged body. For example, the first diagram below shows that a positive test charge is repelled from a positive central charge (+Q). The second diagram shows that the same positive test charge is attracted to a negative central charge (-Q).<\/p>\n<p><center><img decoding=\"async\" src=\"http:\/\/americanboard.org\/Subjects\/Images\/gensci\/img\/Mod5Fig23s.jpg\" alt=\"Positive and negative central charges\" \/><\/center>Mod5Fig23s<\/p>\n<p><center><\/center><\/p>\n<ul>\n<li>Electric field lines always begin at and point away from positive charges. They point toward and end at negative charges.<\/li>\n<li>The number of field lines entering or leaving a charge is representative of the magnitude of each charge.<\/li>\n<li>Field lines never cross.<\/li>\n<li>The electric field is stronger in regions where the field lines are closer together and weaker in regions where the lines are far apart.<\/li>\n<li>Electric field lines are perpendicular to the surface of the charged, conducting object<\/li>\n<li>Electric field lines do not exist within a charged, conducting object.<\/li>\n<\/ul>\n<p>For example, what would the electric field pattern look like if two protons (+2e) were in the vicinity an electron (-e)? The following diagram will show the pattern:<\/p>\n<p><center><img decoding=\"async\" src=\"http:\/\/americanboard.org\/Subjects\/Images\/gensci\/img\/Mod5Fig24s.jpg\" alt=\"Electric field pattern\" \/><\/center>Some of the field lines that leave the positive charge connect to the negative charge and some extend beyond the scale of the drawing.<\/p>\n<p>What do field lines look like in the vicinity of two repelling charges? For example, the following diagram shows the electric field pattern in the vicinity of a +6 Coulomb charge and a +4-Coulomb charge:<\/p>\n<p><center><img decoding=\"async\" src=\"http:\/\/americanboard.org\/Subjects\/Images\/gensci\/img\/Mod5Fig25s.jpg\" alt=\"+6 and +4 Coulomb charges\" \/><\/center>Notice how the field lines never cross. Also, notice the empty region of space between the charges. This indicates that the electric field is weak in the region between the charges (in fact, there is a point nearer to the +4C charge where the electric field is zero).<\/p>\n<section class=\"question\">\n<h4>Question<\/h4>\n<p>Now try sketching the electric field line pattern in the vicinity of a -50C and a -100C charge.<\/p>\n<p><a class=\"button button-primary q-answer\"> Reveal Answer <\/a><\/p>\n<p class=\"q-reveal\"><img decoding=\"async\" src=\"http:\/\/americanboard.org\/Subjects\/Images\/gensci\/img\/Mod5Fig26s.jpg\" alt=\"\" \/><\/p>\n<\/section>\n<h3>Electromotive Force<\/h3>\n<p>Previously we covered that work is done when forces displace objects. When this occurs energy is transferred from one storage mode into another. In this lesson, we will study how energy is transferred in electrical circuits caused by electromotive force.<\/p>\n<p>Electrical circuits may be powered by a variety of energy sources. Here are a few examples of devices that serve as energy sources for circuits:<\/p>\n<ul>\n<li>Batteries: Devices that transfer chemical energy to electrical energy.<\/li>\n<li>Generators: Devices that transfer mechanical energy to electrical energy.<\/li>\n<li>Solar panels: Devices that transfer radiant energy to electrical energy.<\/li>\n<\/ul>\n<p>Each of these devices applies an <abbr title=\"the maximum voltage a power supply is capable of producing. The emf enables a power supply to do work to transfer energy into electrical energy.\">electromotive force (EMF)<\/abbr> that does the work on the electrons in the circuit to transfer energy.<\/p>\n<p>The wires in a circuit provide a pathway for energy transfer. For example, using a simple circuit between a battery and a light bulb, the electrons within the circuit carry energy from the battery to the bulb. These electrons are never created nor destroyed during the process of transferring the chemical energy in the battery to radiant energy shining from the bulb. In a circuit powering an electric blanket, for example, electrical energy is transferred to heat energy.<\/p>\n<p>The electromotive force (EMF) is the potential energy per unit charge that can be transferred to the electrons in a circuit. The units are \u201cjoules per coulomb,\u201d which is defined to be a volt. The EMF is measured by finding voltage, or electric potential difference, across the two ends of the power supply when there are no electrons flowing. If current is running through the power supply, the voltage measurement is actually less than the EMF. Thus, the EMF is the maximum possible potential difference measured across a power source.<\/p>\n<section class=\"question\">\n<h4>Question<\/h4>\n<p>A 9.0-Volt battery establishes current in a simple circuit. Which of the following measurements are possible if a voltmeter is placed across the battery in the circuit?<\/p>\n<ol>\n<li>8.5 V<\/li>\n<li>9.0 V<\/li>\n<li>9.5 V<\/li>\n<li>All of the above are possible.<\/li>\n<\/ol>\n<p><a class=\"button button-primary q-answer\"> Reveal Answer <\/a><\/p>\n<p class=\"q-reveal\">The correct answer is A. The maximum possible voltage measurement is the EMF (9.0 Volts) and this is measured with no current in the battery. When current is flowing, the voltage drops because of the internal resistance of the battery. Therefore, 8.5 V is the only possible measurement in the options given.<\/p>\n<\/section>\n<h3>Electric Current<\/h3>\n<p>Previously you have seen that an electromotive force is responsible for providing the potential to move electrons in a circuit. You also learned that electrons are charged particles that carry energy in a circuit. In this lesson, we will formally define the concept of electric current.<\/p>\n<p>When there is a difference of pressure across the two sides of a water pipe, water will flow from a region of higher pressure to a region of lower pressure. Thus, water current is established in the pipe, and this current is measured in gallons per second. Likewise, when there is a difference of electric potential (voltage) across a wire, electrical current is established. <abbr title=\"a measure of the Coulombs of electrical charge that pass through a cross section in a circuit per second.\">Electric current (I)<\/abbr> is a measure of the number of electrons (measured in Coulombs Q) that pass a point in a circuit over a certain amount of time (t). The equation is written like this:<\/p>\n<p class=\"formula\">I = Q \/ t<\/p>\n<p>The units of electrical current are Coulombs per second which is defined as the Ampere (A).<\/p>\n<p>Electrical current may be classified as \u201cdirect\u201d or \u201calternating.\u201d <abbr title=\"a movement of electrons in one direction throughout a circuit.\">Direct current (DC)<\/abbr> occurs when the electrons circulate in one direction throughout the circuit. Batteries naturally produce DC current. The electrons move quickly in a DC circuit, but the energy they carry is transmitted almost instantaneously throughout the circuit. <abbr title=\"a movement of electrons back and forth at a particular frequency in a circuit.\">Alternating current (AC)<\/abbr> occurs when the electrons vibrate back and forth at a particular frequency. Generators naturally produce AC current. As we shall see in a later lesson, AC current is typically used when a significant amount of energy is transferred through long distances.<\/p>\n<section class=\"question\">\n<h4>Question<\/h4>\n<p>25 Coulombs of electrical charge moves through a cross-section of wire every 5 seconds. What is the current in the wire?<\/p>\n<ol>\n<li>0.2 A<\/li>\n<li>5 A<\/li>\n<li>125 A<\/li>\n<li>More information is needed to determine the current.<\/li>\n<\/ol>\n<p><a class=\"button button-primary q-answer\"> Reveal Answer <\/a><\/p>\n<p class=\"q-reveal\">The correct answer is B and is calculated as follows: I = Q \/ t = (25 C) \/ (5 s) = 5 C \/ s = 5 A<\/p>\n<\/section>\n<h3>Resistance and Ohm\u2019s Law<\/h3>\n<p>When electrons move in an electric circuit the parts of the circuit resist the movement of the electrons. This property in an electric circuit is called resistance. Some electrical devices allow electrical current to flow easily through them. We say that these devices have a low resistance to the flow of electrons. Devices with a high resistance, on the other hand, resist the flow of current. These devices require a power source with a larger voltage to establish the same current as a low resistance device. Consider a simple circuit consisting of a battery and some device (like a light bulb). As the voltage of the battery increases, the current running through the circuit will increase. The resistance of a device is the ratio of the voltage across it to the current running through it as demonstrated on the following graph:<\/p>\n<p><center><img decoding=\"async\" src=\"http:\/\/americanboard.org\/Subjects\/Images\/gensci\/img\/Mod5Fig27s.jpg\" alt=\"Voltage, current, and resistance\" \/><\/center>A graph with a greater slope indicates that a device has a larger resistance. Devices with greater resistance demand a greater voltage to draw the same current as devices with lower resistance. Ohm\u2019s Law is the equation of the linear graph above:<\/p>\n<p class=\"formula\">y = mx + b<\/p>\n<p class=\"formula\">V = R I + 0<\/p>\n<p class=\"formula\">V = I R<\/p>\n<p>where V = voltage, I = current, and R = resistance.<\/p>\n<p>The measurement unit of resistance is the ohm ( \u03a9 ) and is defined as the ratio of volts to amps.<\/p>\n<section class=\"question\">\n<h4>Question<\/h4>\n<p>What is the resistance in the 30 Amp heating coil of a coffee maker that operates on a 120 V circuit?<\/p>\n<ol>\n<li>0.25 ohms<\/li>\n<li>4.0 ohms<\/li>\n<li>90 ohms<\/li>\n<li>3600 ohms<\/li>\n<\/ol>\n<p><a class=\"button button-primary q-answer\"> Reveal Answer <\/a><\/p>\n<p class=\"q-reveal\">The correct answer is B. The numbers are plugged into Ohm&#8217;s law as follows: R = V\/I = (120 V) \/ (30 Amp) = 4.0 ohms.<\/p>\n<\/section>\n<h3>DC Circuits<\/h3>\n<p>One way to increase the electrical resistance is to put a string of devices in series along the same electrical path. The total resistance of the path is the sum of all the individual resistances in the path as follows:<\/p>\n<p><center><img decoding=\"async\" src=\"http:\/\/americanboard.org\/Subjects\/Images\/gensci\/img\/Mod5Fig28s.jpg\" alt=\"DC Circuit\" \/><\/center>With the extra resistance in the circuit, the current running from a power source will drop.<\/p>\n<p>Circuits can also be wired in parallel where there are multiple paths for the electrons to take. With the extra pathways, the resistance of the circuit drops as follows:<\/p>\n<p><center><img decoding=\"async\" src=\"http:\/\/americanboard.org\/Subjects\/Images\/gensci\/img\/Mod5Fig29s.jpg\" alt=\"Parallel circuits\" \/><\/center>The total resistance in parallel is always less than the least resistant path. Because of their low resistance, these circuits tend to draw large currents from power sources.<\/p>\n<p>Most electrical devices are a combination of series and parallel devices. For example, consider the following combination circuit:<\/p>\n<p><center><img decoding=\"async\" src=\"http:\/\/americanboard.org\/Subjects\/Images\/gensci\/img\/Mod5Fig30s.jpg\" alt=\"Combination circuit\" \/><\/center>The 4 \u03a9 and the 12 \u03a9 devices are wired in parallel, so the can be replaced with an equivalent resistance of:<\/p>\n<p><center><img decoding=\"async\" src=\"http:\/\/americanboard.org\/Subjects\/Images\/gensci\/img\/eq0025M.gif\" alt=\"Resistance\" \/><\/center>Now, the circuit can be simplified as follows:<\/p>\n<p><center><img decoding=\"async\" src=\"http:\/\/americanboard.org\/Subjects\/Images\/gensci\/img\/Mod5Fig31s.jpg\" alt=\"Simplified circuit\" \/><\/center>Since the 9 \u03a9 and the 3 \u03a9 resistors are in series, this circuit has a total resistance of 9\u03a9 + 3\u03a9 = 12\u03a9.<\/p>\n<p>Thus, applying Ohm\u2019s law, the total current drawn by the circuit is:<\/p>\n<p class=\"formula\">I = V \/ R total = (12V) \/ 12 \u03a9 ) = 1 A<\/p>\n<section class=\"question\">\n<h4>Question<\/h4>\n<p>The circuit shown below has a total resistance of 24 \u03a9. What is the total current drawn by the battery?<\/p>\n<p><center><img decoding=\"async\" src=\"http:\/\/americanboard.org\/Subjects\/Images\/gensci\/img\/Mod5Fig32s.jpg\" alt=\"Circuit question\" \/><\/center><\/p>\n<ol>\n<li>0.25 A<\/li>\n<li>4.0 A<\/li>\n<li>5.0 A<\/li>\n<li>144 A<\/li>\n<\/ol>\n<p><a class=\"button button-primary q-answer\"> Reveal Answer <\/a><\/p>\n<div class=\"q-reveal\">\n<p>The correct answer is A. Applying Ohm\u2019s Law to the circuit, we obtain the current by dividing the voltage of the power supply by the total resistance:<\/p>\n<p class=\"formula\">I=V\/R total = (6.0V)\/(24 W ) = 0.25 A<\/p>\n<p>To calculate the total resistance, first determine the resistance of the 4 W and 12 W resistors in parallel. This is 3 W as shown earlier in this lesson. Now the circuit looks like the following series circuit:<\/p>\n<p><center><img decoding=\"async\" src=\"http:\/\/americanboard.org\/Subjects\/Images\/gensci\/img\/Mod5Fig33s.jpg\" alt=\"Circuit answer\" \/><\/center>The total resistance is the sum of all three resistors:<\/p>\n<p class=\"formula\">R total = 9 + 3 + 12 = 24 W<\/p>\n<\/div>\n<\/section>\n<h3>AC &amp; DC Circuits<\/h3>\n<p>Previously we covered that electrical energy is delivered via direct current (DC) or alternating current (AC). In this lesson, we will study the applications that are appropriate for DC and AC.<\/p>\n<p>When current flows through a wire, the wire will heat up because of the wire\u2019s resistance. For applications that require low current flow through short distances, the amount of heating in the wires is negligible. Batteries produce DC and are used to deliver energy through short distances in circuits.<\/p>\n<p>When distributing large amounts of energy to electrical power grids, high currents are needed for energy transmitted at common household voltages (120V). The amount of line heating in the wires is prohibitive with these large currents, costing millions of dollars per mile of wire every hour just to power a medium-sized city. When AC is used, however, step-up transformers increase the transmitting voltage and drop the current to levels where the energy loss due to line heating is acceptable. At the household level, step-down transformers drop the voltages back down to 120V and raise the current to levels demanded by the consumer. Transformers only operate with AC current.<\/p>\n<\/section>\n<p><!-- CONTENT ENDS HERE --><\/p>\n<div class=\"advance\"><a class=\"button button-primary\" href=\"http:\/\/americanboard.org\/Subjects\/general-science\/mechanical-waves\">\u2b05 Previous Lesson<\/a>\u00a0<a class=\"button\" href=\"http:\/\/americanboard.org\/Subjects\/general-science\/physics\">Workshop Index<\/a>\u00a0<a class=\"button button-primary\" href=\"http:\/\/americanboard.org\/Subjects\/general-science\/magnetism-and-electromagnetism\">Next Lesson \u27a1<\/a><\/div>\n<p><a class=\"backtotop\" href=\"#title\">Back to Top<\/a><\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>\u2b05 Previous Lesson\u00a0Workshop Index\u00a0Next Lesson \u27a1 Electricity Electrostatics What is the reason for the warnings printed on gas pumps cautioning us not to get in and out of the car when we\u2019re pumping gas? The reason is that cars pick up electrostatic charges as they run, and the car\u2019s tires insulate that charge from the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":["post-115","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/americanboard.org\/Subjects\/general-science\/wp-json\/wp\/v2\/pages\/115","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/americanboard.org\/Subjects\/general-science\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/americanboard.org\/Subjects\/general-science\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/americanboard.org\/Subjects\/general-science\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/americanboard.org\/Subjects\/general-science\/wp-json\/wp\/v2\/comments?post=115"}],"version-history":[{"count":7,"href":"https:\/\/americanboard.org\/Subjects\/general-science\/wp-json\/wp\/v2\/pages\/115\/revisions"}],"predecessor-version":[{"id":633,"href":"https:\/\/americanboard.org\/Subjects\/general-science\/wp-json\/wp\/v2\/pages\/115\/revisions\/633"}],"wp:attachment":[{"href":"https:\/\/americanboard.org\/Subjects\/general-science\/wp-json\/wp\/v2\/media?parent=115"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}